Suppose 100ml of perchloric acid is neutralized by exacly 46.9 ml of 0.75m lithium hydroxide. what is the concentration of the perchloric acid?

0.352M

Explanation:

First, we need to write a balanced equation for the reaction between perchloric acid and lithium hydroxide. This is shown below:

HClO4 + LiOH —> LiClO4 + H2O

From the balanced equation above, we obtained:

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Va (volume of the acid) = 100mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 46.9 mL

Cb (concentration of the base) = 0.75M

Using CaVa/CbVb = nA/nB, the concentration of the acid can obtained as follow:

CaVa/CbVb = nA/nB

Ca x 100 / 0.75 x 46.9 = 1

Cross multiply to express in linear form

Ca x 100 = 0.75 x 46.9

Divide both side by 100

Ca = (0.75 x 46.9) /100

Ca = 0.352M

Therefore the concentration of the acid is 0.352M

beta decay is the answer