Note that this first question is based on week 9 materials. A 50 mL solution containing 35 mM MnCl2 , 18.0 mM cyclohexylamine, and 66.4 cyclohexylammonium, is titrated with a 40 mM solution of EDTA. Determine the amount of manganese free in solution, as pMn2+ , at the points of the titration indicated below:

idk i’m struggling too

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.