How do i do this? pls i need help and steps

The answer to your question is  ΔH = -44.36 kJ      

Explanation:

Data

H NaOH (s) = -4.26 x 10² kJ/mol

H Na⁺(aq) = -2.4034 x 10² kJ/mol

H OH⁻(aq) = -2.3002 x 10² kJ/mol

Balanced chemical reaction

                NaOH (s)   ⇒     Na⁺(aq)   +   OH⁻(aq)

Process

1.- Write the equation to calculate the enthalpy

             ΔH = ∑H products - ∑H reactants

2.- Substitution

             ΔH = (-2.4034 x 10²) + (-2.3002 x 10²) - (-4.26 x 10²)

-Simplification

             ΔH = -2.4034 x 10² - 2.3002 x 10² + 4.26 x 10²

-Result

              ΔH = -44.36 kJ              

c. 4.54 x 10–12 j happens to be correct