What is the volume of 23.4 grams of nitrogen gas at 750 mmHg and 28 degrees C

V = 20.97 L

Explanation:

Given data:

Mass of nitrogen = 23.4 g

Pressure of gas = 750 mmHg (750/760 = 0.99 atm)

Temperature of gas = 28°C (28+273= 301K)

Volume of gas = ?

Solution:

First of all we will calculate the number  of moles of gas.

Number of moles = mass / molar mass

Number of moles = 23.4 g/ 28 g/mol

Number of moles = 0.84 mol

Now we will calculate the volume:

PV = nRT

V = nRT/P

R = general gas constant = 0.0821 atm.L/mol.K

V = 0.84 mol× 0.0821 atm.L/mol.K× 301 K /  0.99 atm

V = 20.76 L/0.99

V = 20.97 L

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.