11g Na,.0900gh, 2.94 and 5.86 g o (NaOHS)
calculate the Imperial formula
please help me

Na5O4H10S

Explanation:

Data obtained from the question include:

Sodium (Na) = 11g

Hydrogen (H) = 0.9g

Oxygen (O) = 5.86g

Sulphur (S) = 2.94g

To obtain the empirical formula, do the following.

First Divide the above by their individual molar mass

Na = 11/23 = 0.478

H = 0.9/1 = 0.9

O = 5.86/16 = 0.366

S = 2.94/32 = 0.092

Next, divide by the smallest number

Na = 0.478/0.092 = 5

H = 0.9/0.092 = 10

O = 0.366/0.092 = 4

S = 0.092/0.092 = 1

Therefore, the empirical formula is Na5O4H10S

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answerspecific gravity;