At a constant pressure, a 10.0 L volume of gas is cooled from 546 K to 273 K What will be the final volume of this gas, assuming no liquefying occurs?
Select one
a. 10.0L
b. 5.00 L
C 8.00 L
d. 20.01

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

since electrons are negative the answer is neagtaive

it's c (engineer's do their work with mechanical stuff not on any living being)