Calculate the ph of the resulting solution if 26.0 ml of 0.260 m hcl(aq) is added to:

(a) 36.0 ml of 0.260 m naoh(aq)
(b) 16.0 ml of 0.360 m naoh(aq)

So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+

Do u have the n? or maybe the m?

The closer the atoms are to becoming ionic the more highly dense the negatively charged side gets.