Use the following data to answer the question. All values of Ka and Kb below are given for aqueous solutions at 25 °C. Pyridine C5H5N (Kb = 1.7 x 10−9)ammonia NH3 (Kb = 1.8 x 10−5)Phenol C6H5OH (Ka = 1.3 x 10−10)methylamine CH3NH2 (Kb = 4.4 x 10−4)Which of the following is the strongest base?a. C6H5OHb. C5H5Nc. C6H5O−d. CH3NH2

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g