A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the volume of the neon gas?

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C  (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm

V = 20.99 L/  0.37

V = 56.72 L

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.