What is the density of CHCL3 vapor at 1.00atm and 298K?

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

Number of moles (n)

can be written as:

where, m = given mass

M = molar mass

where,

which is known as density of the gas

The relation becomes:

   .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant =

T = temperature of the gas =

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

- decrease the number of plants and animals living in the water.

just did the assignment and the answer was #1 +2 n