What mass of carbon dioxide gas occupies a volume of 81.3 L at 204kPa and a temperature of 95 degrees celcius

The mass of carbon dioxide will be 238.51g

Explanation:

Given:

Volume, V = 81.3 L

Pressure, P = 204 kPa

                P = 204000Pa

Temperature, T = 95°C

                       T = 95 + 273K

                       T = 368K

mass of CO₂, m = ?

According to the gas law:

PV = nRT

where, R is the gas constant

n is the moles

and the value of R = 8.314 X 10³ L⋅Pa⋅K⁻¹⋅mol⁻¹

n = m/w

where,

m is the mass of the substance

w is the molecular weight

and molecular weight of CO₂ is 44 g

On substituting the value we get:

Therefore, the mass of carbon dioxide will be 238.51g

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

the answer is true. hope it .