When aqueous solutions of sodium cyanide and hydrobromic acid are mixed, an aqueous solution of sodium bromide and hydrocyanic acid results. Write the net ionic equation for the reaction.

CN⁻(aq) + H⁺(aq) → HCN(l)

Explanation:

The reactants are aqueous solutions:

NaCN(aq) and HBr(aq)

When you mix these compounds you make pure HCN (l)

The molecular equation is:

NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(l)

When you dissociate the reactants, you have:

Na⁺(aq) +CN⁻(aq) + H⁺(aq) + Br⁻(aq) → Na⁺(aq) + Br⁻(aq) + HCN(l)

Sodium bromide, it is a salt, that can also be dissociated in the solution

To make, the net ionic equation you remove the repeated ions

CN⁻(aq) + H⁺(aq) → HCN(l)

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.