What is the molarity of a 2.0L solution that was made up with 4.0 moles of NaCl?

[NaCl]: 2M

Explanation:

This solution is made of NaCl therefore:

Our solute is NaCl

Moles of solute: 4

Our solution's volume is 2L

Molarity are the moles of solute contained in 1L of solution (mol/L)

[NaCl]: 4 mol /2L = 2M

We can also make a rule of three:

In 2 L we have 4 moles of solute

So, In 1 L we must have (1 . 4) /2 = 2 M

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

the answer is 75.0%.