Chemistry, 03.04.2020 22:39 vaehcollier
The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equation: C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g) At 523 K, the value of its equilibrium constant is K = 0.558. (a) Suppose that 1.20 g of benzyl alcohol is placed into a 2.00 L vessel and heated to 523 K. What is the partial pressure of benzaldehyde when equilibrium is attained? (b) What fraction of benzyl alcohol is dissociated into products at equilibrium?
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Chemistry, 22.06.2019 12:10
Consider the reaction: n2(g) + o2(g) ⇄ 2no(g) kc = 0.10 at 2000oc starting with initial concentrations of 0.040 mol/l of n2 and 0.040 mol/l of o2, calculate the equilibrium concentration of no in mol/l how would this be done?
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Can someone me with 6 to 10 plz this is for masteries test.
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Chemistry, 22.06.2019 14:40
Choose an equation that represents an enzyme-catalyzed reaction. (a) enzyme + substrate → enzyme-substrate complex (b) enzyme + substrate ←−→ enzyme + products (c) enzyme + substrate ←−→ enzyme-substrate complex → enzyme + products (d) enzyme + substrate ←−→ enzyme-substrate complex → enzyme-substrate complex + products
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The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium pro...
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