Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of 0.725 M/min. The reaction is observed to follow zero-order kinetics. If the initial concentration of the hydrocarbon is 5.90 M, what is the half-life of the reaction in seconds? *Please report 3 significant figures. Numbers only, no unit. No scientific notation.
Answers: 3
![t_{1/2}=\frac{[A_o]}{2k}](/tpl/images/0582/1472/b5b11.png)
= half-life of the reaction = ?![[A_o]](/tpl/images/0582/1472/dc622.png)
= initial concentration = 5.90 M
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