How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃?
3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)

0.35g

Explanation:

As you can see, you'd need

0.02625

moles of potassium hydroxide in order for all the moles of iron(III) hydroxide to react. Since you have fewer moles of potassium hydroxide than you'd need, potassium hydroxide will act as a limiting reagent.

will take part in the reaction. Since iron(III) nitrate and iron(III) hydroxide are in a

1

:

1

mole ratio in the balanced chemical reaction, you can say that the reaction will produce

0.00330

moles of iron(III) hydroxide.

Use the compound's molar mass to convert this to grams