15.3 grams of Lithium is dropped into a solution containing excess copper II phosphate. When the reaction is completed, 1.25 grams of copper is formed. What is the percent yield?

The answer to your question is 1.8 %

Explanation:

Data

mass of Li = 15.3 g

mass of Cu = 1.25 g

Percent yield = ?

-Balanced chemical reaction

                 6Li  +  Cu₃(PO₄)₂   ⇒   2Li₃PO₄  +  3Cu

-Calculate the theoretical yield of Cu

molar mass of Li = 6 x 6.94 = 41.64 g

molar mass of Cu = 3(63.55) = 190.65 g

                           41.64 g of Li 190.65 g of Cu

                            15.3 g of Li x

                                x = (15.3 x 190.65) / 41.64

                                x = 70.05 g of Cu

-Calculate the percent yield

Percent yield = 1.25/70.05 x 100

                      = 1.8 %

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