8.00 L of sulfur hexafluoride gas are heated from 225K to 350K. If the pressure and number of gas particles do not change, what is the new volume after the temperature increase? 1.00 x 103 L 1.02 x 10-4 L 12.4 L 5.14 L

12.4L

Explanation:

Given parameters:

T₁  = 225K

T₂  = 350K

V₁ = 8L

Unknown:

V₂ = ?

Solution:

Since this heating takes place under constant pressure, we can resolve this temperature and volume relationship using Charles's law.

According to this law "the volume of a gas is directly proportional to the temperature provided that pressure is constant".

 Mathematically, we have;

Input the parameters and solve for the unknown;

     V₂   = 12.4L

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.