If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum
number of grams of iron (III) chloride that can be produced?

2 Fe + 3 Cl2 → 2 FeCl3

84.34 grams of grams of iron (III) chloride that can be produced is maximum because Fe is the limiting reagent in this reaction and chlorine gas is excess reagent.

Explanation:

Balanced chemical equation:

2 Fe + 3 Cl2 → 2 FeCl3

DATA GIVEN:

iron =  atoms

mass of chlorine gas = 67.2 liters

mass of FeCl3 = ?

number of moles of iron will be calculated as

number of moles =

number of moles =

number of moles = 0.52 moles of iron

moles of chlorine gas

number of moles =

Putting the values in the equation:

n =               (atomic mass of chlorine gas = 70.96 grams/mole)

   = 947.01 moles

Fe is the limiting reagent so

2 moles of Fe gives 2 moles of FeCl3

0.52 moles of Fe will give

=

0.52 moles of FeCl3 is formed.

to convert it into grams:

mass = n X atomic mass

         = 0.52 x 162.2                   (atomic mass of FeCl3 is 162.2grams/mole)  

law of conservation of matter