An acid with a H+ molarity of 1x10^-3 M has a PH of?

The answer to your question is pH = 3

Explanation:

Data

[H⁺] = 1 x 10⁻³

pH = ?

pH is a measure of the hydrogen concentration. It measures the acidity or alkalinity. The range of pH goes from 0 to 14. The pH for an acid is from 0 to 6.9, for a neutral solution is 7.0 and for an alkali is from 7.1 to 14.

Formula

             pH = -log [H⁺]

-Substitution

             pH = -log [1 x 10⁻³]

-Simplification

             pH = - (-3)

-Result

             pH = 3

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol