What is the scaling factor if the molar mass of this compound, having an empirical formula of ch2o, is 150 g/mol

The scaling factor is 5

Considering the question given above, the following data were obtained:

Empirical formula = CH₂O

Molar mass of compound = 150 g/mol

The scaling factor can be obtained as follow:

[CH₂O]n = 150

[12 + (2×1) + 16]n = 150

[12 + 2 + 16]n = 150

30n = 150

Therefore, the scaling factor is 5

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The answer to your question is Scaling factor = 5

Explanation:

Data

Empirical formula CH₂O

molar mass = 150 g/mol

Empirical formula is a chemical formula that shows the simplest proportions of the elements of that formula.

Process

1.- Calculate the molar mass of the Empirical formula

    CH₂O = (12 x 1) + (2 x 1) + (16 x 1)

               = 12 + 2 + 16

               = 30 g

2.- Divide the molar mass of the molecular formula by the molar mass of the empirical formula.

                   150g / 30g = 5      Scaling factor = 5

3.- Molecular formula

                    5(CH₂O) = C₅H₁₀O₅

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