URGENT.
Calculate the final pressure inside a scuba tank after it heats from 323 K to 523 K. The initial pressure in the tank is 45.0 atm.

If a gas is pressurized from 10.0 atm to 12.0 atm and the final temperature is at standard temperature (273.15 K), what was the initial temperature of gas?

1. 72.9 atm

2. 0.43937 K

Explanation:

1. Gray- lussacs law is p1/t1=p2/t2 so we use this formula to figure it out by filling in the variables and solving

p1=45.0 atm

t1=323 K

p2= ?

t2=523 K

Now we fill in this in the formula and solve - 45.0 atm/ 323 K = p2/ 523 K

and now we solve for p2 by multiplying 535k by each side to give us p2

2. Using the same formula we get 10.0atm/? = 12.0 atm/ 273.15 k and we divide both sides by 10.0 atm

i wish i could but this one is weird give me abc and i can solve it.

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