Determine the limiting reactant for the reaction of sodium carbonate and nickel(II) chloride using the quantities listed below. 6.279 g solid nickel(II) chloride 500.0 mL of 0.1010 M sodium carbonate

The limiting reactant is the 6.279 g of

Explanation:

We have to start with the reaction between sodium carbonate () and the Nickel (II) Chloride (), so:

We will have a double replacement reaction. Now we have to balance the reaction, so:

The next step is the calculation of the moles for each reactive. For we have use the molarity equation:

For the calculation of moles of we have to use the molar mass of the compound (129.59 g/mol):

The next step is the division of each mole value by the coefficient of each reactive of the balance reaction. In this case we have "1" for each reactive, so:

The final step is to choose the smallest value. In this case is the value that correspond to . Therefore is the limiting reactive.

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atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8