An aqueous potassium carbonate solution is made by dissolving 5.51 moles of K 2 CO 3 in sufficient water so that the final volume of the solution is 3.30 L . Calculate the molarity of the K 2 CO 3 solution.

1.67mol/L

Explanation:

Data obtained from the question include:

Mole of solute (K2CO3) = 5.51 moles

Volume of solution = 3.30 L

Molarity =?

Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:

Molarity = mole of solute /Volume of solution

Molarity = 5.51 mol/3.30 L

Molarity = 1.67mol/L

Therefore, the molarity of K2CO3 is 1.67mol/L

The molarity of the K2CO3 solution = 1.67 M

Explanation:

Step 1: Data given

Number of moles K2CO3 = 5.51 moles K2CO3

Volume of the solution = 3.30 L solution

Step 2: Calculate the molarity of the solution

Molarity = Number of moles K2CO3/ volume of solution

⇒Molarity = in mol/l = M = TO BE DETERMINED

⇒Number of moles K2CO3 = 5.51 moles K2CO3

⇒Volume of the solution = 3.30 L

Molarity K2CO3 solution = 5.51 moles / 3.30 L

Molarity K2CO3 solution = 1.67 mol/L = 1.67 M

The molarity of the K2CO3 solution = 1.67 M

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