A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is the new pressure, if volume and amount of gas do not change?

The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

where,

are the initial pressure and temperature of the gas.

are the final pressure and temperature of the gas.

We are given:

Putting values in above equation, we get:

Thus the new pressure, if volume and amount of gas do not change is  2.40 atm

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.