How many moles of NaCl will be produced from 59.0 g of Na assuming Cl2 is available is excess

The answer to your question is  2.56 moles of NaCl

Explanation:

Data

moles of NaCl = ?

mass of Na = 59 g

mass of Cl₂ = excess

Process

1.- Write the balanced chemical reaction

              2Na  +  Cl₂  ⇒   2NaCl

2.- Calculate the atomic mass of Na

Na = 23 g

3.- Convert the mass of Na to moles

                     23 g of Na 1 mol

                     59 g of Na  x

                            x = (59 x 1)/23

                            x = 2.56 moles

4.- Calculate the moles of NaCl using the coefficient s of the balanced equation.

                  2 moles of Na 2 moles of NaCl

                  2.56 moles of Na x

                                      x = (2.56 x 2) / 2

                                      x = 2.56 moles of NaCl

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