If the temperature of water at 30∘c is raised by 1∘c, the water will expand. at approximately what initial temperature t will water expand by twice as much when raised by 1∘c?

Hello

This is an example of charles's law equation.

This law established that when the temperature increases, the volume also increases in a proportional relationship.

Let's see the equation:

V1*T2=V2*T1

Where:

V1= initial volume

V2= final volume

T1= Initial temperature

T2=FInal temperature

So, let's suppose that we have an original volume of 2 L and, where the temperature raised by 1°C it expand by twice to 4 L:

Replacing the values of charles's equation as follow:

V1= 2L

V2 =4L

T1 = x (because we don't know the value yet... )

and, as we want to raise the temperature by 1°C:

T2= x +1°C:

Going back to the charles's equation and replacing:

2L*(x+1°C)=4L*x

Then, we have to solve the equation as follow:

2x+2=4x

All terms with x has to be on one side of the equation:

2=4x-2x

2=2x

x=1°C

So the answer is initial temperature= 1°C.

Let's probe this anwer, using charles's law equation with any volume, for example V1= 5L

5L*2°C=V2*1°C

Solving:

V2=5L*2°C/1°C

V2=10L

So for ANY volume value, to expand by twice as much when raised by 1°C the initial temperature has to be 1°C.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

one negative thing it that it can kill water animals. another negative thing is it can cause the destruction of ecosystem. one way water pollution can be reduced is to conserve energy.