How many grams of magnesium oxide can be produced if 25.0 g of magnesium are allowed to react with 28 g of oxygen?

2Mg + O2 —> 2MgO

Answer : The mass of produced is, 41.68 grams.

Explanation : Given,

Mass of = 25.0 g

Mass of = 28 g

Molar mass of = 24 g/mol

Molar mass of = 32  g/mol

First we have to calculate the moles of and .

and,

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

From the balanced reaction we conclude that

As, 2 mole of react with 1 mole of

So, 1.042 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 2 mole of

So, 1.042 mole of react to give 1.042 mole of

Now we have to calculate the mass of

Molar mass of = 40 g/mole

Therefore, the mass of produced is, 41.68 grams.

10 years is the answer

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.