- A sample of 100.0 ml of oxygen has a pressure of 10.50 kPa. If the pressure is
changed to 9.91 kPa, what is the new volume of the gas?

The answer to your question is 106 ml

Explanation:

Data

Volume 1 = 100 ml

Pressure 1 = 10.5 kPa

Volume 2 = ?

Pressure 2 = 9.91 kPa

Process

To solve this problem use Boyle's law.

               Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Solve for Volume 2

               Volume 2 = Pressure 1 x Volume 1 / Pressure 2

-Substitution

               Volume 2 = 10.5 x 100 / 9.91

-Simplification

               Volume 2 = 1050 / 9.91

-Result

               Volume 2 = 105.95 ml ≈ 106 ml

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the answer to your question is c.

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