What is the mass of solute in 500mL solution of 0.200M sodium phosphate (Na3PO4: M. W. 164.0)?

16.4g of solute is present in 500mL of the solution.

Explanation:

Given:

Volume of solution, V = 500mL = 0.5L

Molarity of Sodium phosphate, M = 0.2M

Molecular weight of Na₃PO₄ = 164 g/mol

Mass of the solute, m = ?

We know:

And

Number of moles =

On substituting the value we get:

Therefore, 16.4g of solute is present in 500mL of the solution.

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