A volume of gas occupies 1.2 L at 5.1 kPa. What volume would the gas occupy at 2.2 kPa?

2.78 L

Explanation:

Given that,

Original volume V1 = 1.2 L

Original pressure P1 = 5.1 kPa

New pressure P2 = 2.2 kPa

New volume V2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

5.1 kPa x 1.2L = 2.2 kPa x V2

6.12 kPa L = 2.2 kPa x V2

V2 = 6.12 kPa L / 2.2L

V2 = 2.78 L

Thus, the new volume of the gas would be 2.78 Liters

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons