Remember what the equation is:
MOLARITY = MOLES SOLUTE/LITERS OF SOLUTION
Solute = what you dissolve (in our example, glucose)
LET
Solvent = what does the dissolving (in our example, water)
ments
Solution = the mixture of the two (sugar water!)
Let's start with an easy example. Suppose you weighed out 25 g of glucose
(CH20)
1. How many moles of glucose did you weigh out?
2. If you added enough water to make 1 liter of solution, what would be the
molarity of the solution you made?
3. Suppose instead you took 25 g of glucose and only added enough water to
make 500 mL of solution. What would be the molarity of that solution?
4. Lastly, what if you took 25 g of glucose and added enough water to make 2
liters of solution. What would the molarity be?

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.