A sample of gas has a volume of 1.16L at a temperature of 23C. At what temperature will the gas have a volume of 1.25L?

T₂ = 319.13 K

Explanation:

Given data:

Initial volume of gas = 1.16 L

Initial temperature = 23°C

Final temperature = ?

Final volume = 1.25 L

Solution:

Initial temperature = 23°C (23+273.15 = 296.15 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  = V₂ T₁ / V₁

T₂ = 1.25 L × 296.15 K / 1.16 L

T₂ = 370.19 L.K /  1.16 L

T₂ = 319.13 K

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