Calculating grams:

If you wanted to make 0.800 Liters of a 0.531 M solution of Nickel (II) chloride, NiCl2, how many grams of NiCl2 would you need?
M = 0.531 M
n = 0.4248 mol
V = 0.800 L

n = M x V 0.4248 = 0.531 x 0.800

Now that you know the number of moles, you will need the molar mass of NiCl2 to calculate the grams of NiCl2.

Ni = 58.6934 = 59
Cl = 35.453 x 2 = 35 x 2 = 70
NiCl2 = 129 g/mol

Now use the unit canceling method to determine the grams of NiCl2 required:

.4248 mol NiCl2 x 129 g NiCl2 / 1 mol NiCl2 = 54.799 g NiCl2

Is this correct??

The answer to your question is 55.224 g of NiCl₂

Explanation:

I will solve it and then I compare the results.

Data

Volume = 0.8 l

Molarity = 0.531

substance = NiCl₂

Process

1.- Calculate the molar mass of NiCl₂

NiCl₂ = 59 + (35.5 x 2)

         = 130 g

2.- Calculate the number of moles

Molarity = moles / volume

-Solve for moles

  moles = Molarity x volume

-Substitution

  moles = 0.531 x 0.8

-Result

  moles = 0.4248

3.- Convert the moles to mass

                   130 g 1 mol of NiCl₂

                      x     0.4248 moles

                           x = (0.4248 x 130) / 1

-Simplifying

                         x = 55.224 / 1

-Result

                        x = 55.224 g of NiCl₂

4.- We need 55.224 g of NiCl₂ to prepare 0.8l of a solution 0.531 M.

You have similar results, just our molar mass is different.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.