How many moles of Ag will be produced from 46.0 g of Cu, assuming AgNO3 is available in excess?

1.44 mol

Explanation:

Given data:

Mass of Cu = 46 g

Moles of Ag produced = ?

Solution:

Chemical equation:

Cu + 2AgNO₃      →     2Ag  + Cu(NO₃)₂

Number of moles of Cu:

Number of moles = mass/ molar mass

Number of moles = 46 g/63.546 g/mol

Number of moles = 0.72 mol

Now we will compare the moles of Cu and silver from balance chemical equation:

                 Cu           :               Ag

                  1             :                2

               0.72         :             2×0.72 = 1.44 mol

Thus from 46 g of Cu 1.44 moles of Ag is produced .

idk what the question is about