When NH3(g) reacts with O2(g) according to the following reaction, 226 kJ of energy are evolved for each mole of NH3(g) that reacts. Complete the following thermochemical equation. 4NH3(g) + 5O2(g)4NO(g) + 6H2O(g) H = kJ

4NH₃ + 5O₂   →  4NO + 6H₂O    ΔH = -904 kj

Explanation:

Given data:

Energy evolved when one mole of NH₃ react = 226 kj

Energy evolved when 4 mole of NH₃ react =  ?

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O      

It is stated in question that when one mole of ammonia react 226 kj energy evolved.

When 4 moles react energy evolved is,

1 mol = -226 kj

4 mol × -226 kj / 1mol

-904 kj

when 4 moles of ammonia react 904 kj energy is evolved.

Complete thermal equation:

4NH₃ + 5O₂   →  4NO + 6H₂O    ΔH = -904 kj

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante

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