A 4.75 Liter container is at a pressure of 120 kPa. What will its pressure be at a volume of 1.85L?

The answer to your question is 308.1 kPa

Explanation:

Data

Volume 1 = V1 = 4.75 l

Pressure 1 = P1 = 120 kPa

Volume 2 = V2 = 1.85 l

Pressure 2 = ?

Process

To solve this problem use Boyle's law.

                 P1V1 = P2V2

- Solve for P2

                 P2 = P1V1 / V2

- Substitution

                 P2 = (120 x 4.75) / 1.85

-Simplification

                 P2 = 570 / 1.85

-Result

                  P2 = 308.1 kPa

*tilts head* sounds more like a statement

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.