5) Determine the mass in gram of 1.33 x 10^22 gram of Sb?

I need the answer for that plz help

I believe it's 2.70 grams

Explanation:

First, divide 1.33 x 10^22 by 6.022 x 10^23. 6.022 x 10^23 is Avogadro's constant of 1 mole of any atoms. After you divide, you get 2.208568582 x 10^-2 which you should round the the nearest hundredth which is 2.21 x 10^-2. Second, because of Sb or Antinomy atomic mass is 121.760, round it up to the whole number which is 122. Therefore, multiply 122 and 2.21 x 10^-2 which it'll equal to 2.6962 x 10. Finally, round it up and you'll get 2.70 grams. Hope that helps!