A gas occupies 35 liters at a temperature of 75°C. What will its volume
be if it's cooled to 25°C? Assume pressure stays constant.

30 liters

Explanation:

Given that,

Original volume of gas (V1) = 35L

Original temperature of gas (T1) = 75°C

[Convert 75°C to Kelvin by adding 273

75°C + 273 = 348K]

New volume of gas (V2) = ?

New temperature of gas (T2) = 25°C

[Convert 25°C to Kelvin by adding 273

25°C + 273 = 298K]

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

35L/348K = V2/298K

To get the value of V2, cross multiply

35L x 298K = 348K x V2

10430L•K = 348K•V2

Divide both sides by 348K

10430L•K /348K = 348K•V2/348K

29.97 L = V2

Round the volume to the nearest whole number, So V2 becomes 30L

Thus, the new volume will be 30 liters

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.