What is the product of the reaction between HCIO3 and KOH

The products are: KCl03 and H20.

Explanation:

The reaction between HC03 (chloric acid) and KOH (potassium hydroxide) is:

HC03  + KOH > KCl03 (KCl03 and H20) + H20 (water)

The reaction is of the double displacement type (in this case parts of the reagents are exchanged, producing two generating new compounds).

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.