Chemistry, 14.04.2020 07:44 aide1234564

1.Complete the balanced neutralization equation for the reaction below:
H2SO4 (aq) + Sr(OH)2 (aq) -->

2. How many L of a 0.209 M KI solution is needed to completely react with 2.43 g of Cu(NO3)2 according to the balanced chemical reaction:
2Cu(NO₃)₂(aq) + 4KI(aq) → 2CuI(aq) + I₂(s) + 4KNO₃(aq)

3.What volume in L of a 0.724 M Nal solution contains0.405 mol of Nal?

4. How many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water?

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Answers

Answer from: Oliviapuffinburger33

1. $H_{2}$ S $O_{4}$ + Sr(OH) $_{2}$ ⇒ SrSO4 + 2 H2O is the balanced reaction.

2. 0.034 liters of KI will be required completely react with 2.43 g of Cu(NO3)2.

3. 0.55 liters is the volume in L of a 0.724 M Nal solution contains0.405 mol of NaI.

4. 33.3 ml many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water

Explanation:

Balance chemical reaction of neutralization:

1. $H_{2}$ S $O_{4}$ + Sr(OH) $_{2}$ ⇒ SrSO4 + 2 H2O

2. Data given:

balance chemical reaction:

2Cu(NO₃)₂(aq) + 4KI(aq) → 2CuI(aq) + I₂(s) + 4KNO₃(aq)

molarity of KI = 0.209 M

mass of Cu(NO₃)₂ = 2.43 grams

number of moles of Cu(NO₃)₂ will be calculated as:

number of moles = $\frac{mass}{atomic mass of 1 mole}$

atomic mass of Cu(NO₃)₂ = 187.56 grams/mole

putting the values in the equation,

number of moles= $\frac{2.43}{187.56}$

= 0.0129 moles

2 moles of Cu(NO₃)₂ will react with 4 moles of KI

0.0129 moles will react with x moles of KI

$\frac{4}{2}$ = $\frac{x}{0.0129}$

x = 0.0258

atomic mass of KI = 166.00 grams/mole

mass = 166.00 x 0.0258

= 4.28 grams or ml is the final volume of KI

so molarity = $\frac{number of moles}{volume in litres}$

so molarity of KI is 0.0258 M, volume is 1 litre.

Using the formula

Minitial x Vinitial = M final Vfinal

V initial = $\frac{M final Vfinal}{Minitial}$

= $\frac{4.28 X 0.209}{0.0258}$

= 34.67 ml 0.034 liters of KI will be required.

3) Data given:

molarity of NaI = 0.724

number of moles of NaI =?

Volume in litres =?

formula used:

molarity = $\frac{number of moles}{volume in liters}$

volume in litres = $\frac{0.405}{0.724}$

= 0.55 liters is the volume

4) Data given:

Initial molarity = 0.3 M

initial volume = ?

final molarity = 0.04 M

final volume diluted by = 250 ml

formula used:

M initial X Vinitial = Mfinal X V final

putting the values in the equation:

Vinitial = $\frac{0.04 X 250}{0.3}$

= 33.3 ml of 0.3 M solution will be required.

Answer from: Quest

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.

Answer from: Quest

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