A gas occupying a volume of 425 mL at a pressure of 2 atm is allowed to expand until the pressure reaches 588 mmHg. What is the final volume in mL?

1098.6 mL

Explanation:

Given that,

Initial volume of gas (V1) = 425mL

Initial pressure of gas (P1) = 2 atm

[Since final pressure is given in mmHg, convert 2 atm to mmHg

1 atm = 760 mmHg

2 atm = 2 x 760 = 1520 mmHg]

Final volume of gas (V2) = ?

Final pressure of gas (P2) = 588 mmHg

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

1520 mmHg x 425mL = 588 mmHg x V2

646000 mmHg•mL = 588 mmHg•V2

Divide both sides by 588 mmHg

646000 mmHg•mL/588 mmHg = 588 mmHg•V2/588 mmHg

1098.639 mL = V2

Round the 1098.639 to the nearest tenth, hence it becomes 1098.6

Thus, the final volume of the gas is 1098.6 mL

the atomic mass is the bottom number on the element.

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