Consider the reaction NaCH3COO (sodium acetate in acetic acid) with tert-butyl bromide (2-bromo-2-methylpropane). If the concentration of both the nucleophile/base and the substrate are doubled, what happens to the rate of reaction?

a. it doubles
b. it quadruples
c. new rate = 1/2 of original rate
d. it does not change
e. new rate = 1/4 of original rate

 a. it doubles

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

As the given halide is tertiary halide and the base is strong , it undergoes reaction and thus rate depends only on the concentration of  tert-butyl bromide.

[base]^0

k= rate constant

If concentration of both the base and the substrate are doubled ,

  (2)

Thus the rate of reaction doubles.

lol idk man i guess u gotta ask bill nye the science guy

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.