1) A balloon is filled with helium to a volume of 13.6 Lat a pressure of
101 kPa. If the pressure decreases to 35.0 kPa what is the new volume
of the balloon (assuming temperature is constant)? (Boyle's Law)

Final volume = 835 L

Explanation:

Given data:

Initial volume = 13.6 L

Initial pressure = 101 Kpa

Final pressure = 35.0 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 KPa × 13.6 L = 35 KPa × V₂

V₂ = 1373.6 KPa. L/35 KPa

V₂ = 835 L

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

2b2t

explanation:

2b2t