A 250 mL sample of saturated AgOH solution was titrated with HCl, and the endpoint was reached after 2.60 mL of 0.0136 M of HCl was dispensed. Based on this titration, what is the Ksp of AgOH?

Ksp=1.9×10⁻⁸

Explanation:

First write the balane chemical reaction

AgOH + HCl → AgCl+H2O

Titration reaction occur completely

N-factor of AgOH and HCl is one

normality=molarity

Noermality of HCl=0.0136

N₁ and N₂ are the normality of AgOH and HCl respectively

V₁ and V₂ are the volume of AgOH and HCl respectively

mili equvalent of AgOH-mili equivalent of HCl

=?

=250ml

=0.0136

=2.6ml

after puttting all the value we get,

=0.000141 =normality of AgOH solution

molarity=0.000141M

Calculation of Ksp

AgOH⇄Ag⁺  +  OH⁻

Lets solubility=S

=S

[OH⁻]=S

and S is equal to the concentration of AgOH because that concentration is calculated when solution become satrated.

hence S=0.000141M

Ksp=[Ag+][OH-]

Ksp=S×S

Ksp=1.9×10⁻⁸

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

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