A sample of argon gas at a standard pressure occupies 900 mL at constand temp what volume does the gas occupy if the presure increases to 850mmHg
options:
A 760mL
B 805mL
C 950mL
D 1053mL

B .805 mL

Explanation:

Here, temperature is constant!

so we can use P1V1=P2V2

P1,V1 is pressure and volume in original condition

and P2V2, pressure and volume in new condition!

now, volume is given 900mL(=V1)

standard pressure is 1 atm i.e, 760mmHg(=P1)

pressure increases to 850mmHg(=P2)

now we have,

P1V1=P2V2

i.e, 760mmHg×900mL=850mmHg×V2

i.e, V2={(900×760)/850 } mL

=804.75 mL

≈805mL

✌️:)

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