A sample of ideal gas has a volume of 0.500-L at 25.0o C and 1.20 atm pressure. What is the volume at 75.0o C and 3.60 atm?

.500

Explanation:

Use the ideal gas law equation: PV = nRT

Plug in the initial values given:

P = 1.2 atm

V = .500 L

n = number of moles

R = Gas Constant 8.314

T = 25.0 C

(1.2)(.5) = n(8.314)(25)

solving for n we get .00289

Now use the same equation with the new values solving for V

(3.6)V = (.00289)(8.314)(75.0)

V = .4999999 ROund to .500

1. they vary with a higher number because boiling is way hotter than melting