Suppose two chemical reactions are linked together in a way that the O2 produced inthe first reaction goes on to react completely with Mg to form MgO in the second reaction. Reaction one: 2 KClO3 3 O2→ + 2 KClReaction two: 2 Mg + O2 2 MgO→If you start with 4 moles of KClO3, how many moles of MgO could eventually form?

A) 2 moles
B) 4 moles
C) 6 moles
D) 12 moles
E) none of the above

12 moles of MgO could eventually form.

Explanation:

In the reaction:

2KClO₃ → 3O₂ + 2KCl

2 moles of KClO₃ produce 3 moles of O₂. 4 moles of KClO₃ produce:

4 mol KClO₃ × (3 mol O₂ / 2 mol KClO₃) = 6 mol O₂

In the second reaction:

2Mg + O₂ → 2MgO

1 mole of O₂ produce 2 moles of MgO. Thus, 6 mol of O₂ produce:

6 mol O₂ × (2 mol MgO  / 1 mol O₂) = 12mol MgO

Thus, 12 moles of MgO could eventually form.

do u have any choices to choose from ? ?

the tides are influenced by both the moon and the sun, it's easy to see that when the sun lines up with the moon and the earth, as during a new moon or full moon, the tidal effect is increased. these are known as spring tides, named not for the season, but for the fact that the water "springs" higher than normal. on the other hand, if the sun and the moon are 90 degrees apart in relation to an observer on earth as during the first quarter moon or third quarter moon, then high tides are not as high as they normally would be. this is because despite its greater distance, the sun's mass allows it to exert enough gravitational force on the oceans that it can negate some of the effects of the moon's pull. this phenomenon of lower high tides is called a neap tide. if you need more information on this topic visit moonconnection.com.