When 0.800 grams of NaOH is dissolved in 100.0 grams of water, the temperature of the solution increases from 25.00 oC to 27.06 oC. The amount of heat absorbed by the water is J. (The specific heat of water is 4.18 J/g - oC.)

The amount of heat absorbed by the water is Q = 861.08 Joule

Explanation:

Mass of water = 100 gm

Temperature change ΔT = 27.06 - 25 = 2.06 °c

We know that heat absorbed by the water is given by

Q = m C ΔT

Put all the values in above equation we get

Q = 100 × 4.18 × 2.06

Q = 861.08 Joule

Therefore the amount of heat absorbed by the water is Q = 861.08 Joule

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