Consider the reaction CaCN2 + 3 H2O → CaCO3 + 2 NH3 . This reaction has a 75.6% yield. How many moles of CaCN2 are needed to obtain 18.6 g of NH3?
a. 0.547 mol
b. 209 mol
c. 0.414 mol
d. 1.65 mol
e. 478 mol
f. 0.724 mol

Thus 0.724 mol of are needed to obtain 18.6 g of

Explanation:

To calculate the moles :

According to stoichiometry :

2 moles of are produced by = 1 mole of

Thus 1.09 moles of will be produced by =  of

But as yield of reaction is 75.6 %, the amount of needed is =

Thus 0.724 mol of are needed to obtain 18.6 g of

thats how its supposed to be

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